Question:

Identify the wrong statement

Show Hint

Always remember \(m = IA\), not \(I^2A\).
Updated On: May 8, 2026
  • Current loop is equivalent to a magnetic dipole
  • Magnetic dipole moment of a planar loop of area \(A\) carrying current \(I\) is \(I^2A\)
  • Particles like proton, electron carry an intrinsic magnetic moment
  • The current loop placed in uniform magnetic field experiences torque \(\vec{\tau} = \vec{m} \times \vec{B}\)
  • Ampere’s circuital law is not independent of Biot Savart’s law
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The Correct Option is B

Solution and Explanation

Concept: Magnetic dipole moment of a current loop is defined as: \[ \vec{m} = I \vec{A} \] It depends linearly on current and area.

Step 1:
Check option (A).
A current loop produces a magnetic field similar to a bar magnet → correct.

Step 2:
Check option (B).
Given: \(I^2A\), but correct formula is: \[ m = IA \] Thus this is incorrect.

Step 3:
Check option (C).
Electrons and protons possess intrinsic spin → magnetic moment → correct.

Step 4:
Check option (D).
Torque on dipole: \[ \vec{\tau} = \vec{m} \times \vec{B} \] Correct.

Step 5:
Check option (E).
Ampere’s law can be derived from Biot–Savart law → not independent → correct.

Step 6:
Conclusion. \[ \boxed{(B)} \]
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