Question:

Identify the type of reaction that Converts acetamide to methanamine by using aqueous KOH and \(\text{Br}_{2}\).

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An amide treated with bromine and alkali gives an amine with one carbon atom less.
Updated On: Nov 12, 2026
  • Gabriel phthalimide reaction
  • Hofmann elimination reaction
  • Hofmann exhaustive alkylation reaction
  • Hofmann degradation reaction
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The Correct Option is D

Solution and Explanation

Step 1: Understanding the Concept
Converting an amide to a primary amine with one carbon less using \(\text{Br}_2\) and KOH is called the Hofmann bromamide (degradation) reaction.

Step 2: Apply it
\(\text{CH}_3\text{CONH}_2+\text{Br}_2+4\text{KOH}\rightarrow\text{CH}_3\text{NH}_2+\text{K}_2\text{CO}_3+2\text{KBr}+2\text{H}_2\text{O}\)

Step 3: Check the other names
Gabriel phthalimide synthesis uses phthalimide and alkyl halide, while Hofmann elimination and exhaustive alkylation involve quaternary ammonium compounds.

Final Answer:
The reaction is Hofmann degradation. \[ \boxed{\text{(D) }\text{Hofmann degradation reaction}} \]
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