Question:
Identify the product obtained when RCN is treated with sodium and alcohol.
Identify the product obtained when RCN is treated with sodium and alcohol.
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Na/C$_2$H$_5$OH reduces a nitrile to a primary amine.
Updated On: Oct 1, 2026
- \(\text{RCONH}_2\)
- \(\text{RCOONH}_4\)
- \(\text{RCH}_2\text{NH}_2\)
- \(\text{R}(\text{CH}_2)_3\text{NH}_2\)
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The Correct Option is C
Solution and Explanation
Step 1: Recall the reaction
Sodium with alcohol is a reducing mixture (nascent hydrogen). It reduces \(\text{R-C}\equiv\text{N}\) to \(\text{RCH}_2\text{NH}_2\).
Step 2: Result
The amine has one more carbon than R. Option (C).
Final Answer:
The product is RCH\(_2\)NH\(_2\), option (C). \[ \boxed{\text{(C)}} \]
Sodium with alcohol is a reducing mixture (nascent hydrogen). It reduces \(\text{R-C}\equiv\text{N}\) to \(\text{RCH}_2\text{NH}_2\).
Step 2: Result
The amine has one more carbon than R. Option (C).
Final Answer:
The product is RCH\(_2\)NH\(_2\), option (C). \[ \boxed{\text{(C)}} \]
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