Question:

Identify the species from following that exhibits no bond resonance.

Show Hint

Always associate the phrase "no bond resonance" instantly with hyperconjugation. Look for carbocations, alkenes, or free radicals possessing alpha-hydrogens, as they are classical structural examples that display this electronic behavior.
Updated On: Jun 11, 2026
  • $\mathrm{CH_3CH_2Br}$
  • $\mathrm{\overset{(+)}{C}H_2CH_3}$
  • $\mathrm{CH_3CH_2NO_2}$
  • $\mathrm{C_6H_6}$
Show Solution
collegedunia
Verified By Collegedunia

The Correct Option is B

Solution and Explanation

Step 1: Understanding the Question:
The question asks to identify the species from the given list that undergoes or displays "no bond resonance".

Step 2: Key Formula or Approach:
"No bond resonance" is the historical synonym and alternative name for the concept of

hyperconjugation (also known as the Baker-Nathan effect). It involves the delocalization of $\sigma$-electrons belonging to a $\mathrm{C-H}$ bond of an alkyl group directly into an adjacent unhybridized p-orbital or $\pi$-system. This phenomenon requires at least one $\alpha$-hydrogen attached to an $\mathrm{sp^3}$ carbon adjacent to an $\mathrm{sp^2}$ carbon (carbocation, free radical, or alkene).

Step 3: Detailed Explanation:
Let's evaluate each option to check for hyperconjugation eligibility:

• $\mathrm{CH_3CH_2Br}$: A neutral saturated alkyl halide with no empty p-orbitals or adjacent $\pi$-systems for conjugation.

• $\mathrm{\overset{(+)}{C}H_2CH_3}$ (Ethyl Carbocation): The carbocationic carbon ($\mathrm{- \overset{(+)}{C}H_2}$) is $\mathrm{sp^2}$ hybridized with a vacant p-orbital. The adjacent $\alpha$-carbon ($\mathrm{-CH_3}$) contains three $\alpha$-hydrogens. The $\sigma$-electrons of these $\mathrm{C-H}$ bonds actively delocalize into the vacant p-orbital, illustrating structural hyperconjugation structures (no bond resonance).

• $\mathrm{CH_3CH_2NO_2}$: Saturated compound containing a nitro group, does not typically exhibit hyperconjugation relative to a vacant p-orbital or alkene.

• $\mathrm{C_6H_6}$ (Benzene): Exhibits traditional $\pi$-$\pi$ resonance, not no bond resonance.

Step 4: Final Answer:
The species that displays no bond resonance (hyperconjugation) is the ethyl carbocation $\mathrm{\overset{(+)}{C}H_2CH_3}$, matching option (B).
Was this answer helpful?
0
0