Question:

Identify the set of paramagnetic ions among the following.

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Paramagnetic ions have at least one unpaired d electron.
Updated On: Oct 1, 2026
  • \(\text{V}^{+2},\text{Co}^{+2},\text{Ti}^{+4}\)
  • \(\text{Ni}^{+2},\text{Cu}^{+2},\text{Zn}^{+2}\)
  • \(\text{Ti}^{+2},\text{Cu}^{+2},\text{Mn}^{+3}\)
  • \(\text{Sc}^{+3},\text{Ti}^{+3},\text{V}^{+3}\)
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The Correct Option is C

Solution and Explanation

Step 1: Write configurations
Ti\(^{2+}\): \(3d^2\) (2 unpaired). Cu\(^{2+}\): \(3d^9\) (1 unpaired). Mn\(^{3+}\): \(3d^4\) (4 unpaired).

Step 2: Check the other sets
(A) has Ti\(^{4+}\) (\(3d^0\)), which is diamagnetic.
(B) has Zn\(^{2+}\) (\(3d^{10}\)), which is diamagnetic.
(D) has Sc\(^{3+}\) (\(3d^0\)), which is diamagnetic.
Only (C) has all three paramagnetic.

Final Answer:
All ions in set (C) have unpaired electrons, option (C). \[ \boxed{\text{(C)}} \]
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