Step 1: Write configurations
Ti\(^{2+}\): \(3d^2\) (2 unpaired). Cu\(^{2+}\): \(3d^9\) (1 unpaired). Mn\(^{3+}\): \(3d^4\) (4 unpaired).
Step 2: Check the other sets
(A) has Ti\(^{4+}\) (\(3d^0\)), which is diamagnetic.
(B) has Zn\(^{2+}\) (\(3d^{10}\)), which is diamagnetic.
(D) has Sc\(^{3+}\) (\(3d^0\)), which is diamagnetic.
Only (C) has all three paramagnetic.
Final Answer:
All ions in set (C) have unpaired electrons, option (C).
\[ \boxed{\text{(C)}} \]