Question:
Identify the product Y in the following reaction sequence
\[
C_2H_4 \xrightarrow[(ii)\ AgCN]{(i)\ HBr} X \xrightarrow[\text{Catalyst}]{H_2} Y
\]
Identify the product Y in the following reaction sequence
\[
C_2H_4 \xrightarrow[(ii)\ AgCN]{(i)\ HBr} X \xrightarrow[\text{Catalyst}]{H_2} Y
\]
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Remember: KCN gives nitriles (R-CN), while AgCN gives isocyanides (R-NC). Reduction of isocyanides forms secondary amines.
Updated On: Jul 29, 2026
- n-propyl amine
- Isopropyl amine
- Ethyl amine
- Ethyl methyl amine
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Verified By Collegedunia
The Correct Option is D
Solution and Explanation
Step 1: Reaction of ethene with HBr
Ethene reacts with HBr to form:
\[
CH_3CH_2Br
\]
So,
\[
X = \text{Bromoethane}
\]
Step 2: Reaction with AgCN Alkyl halides with AgCN give isocyanides: \[ CH_3CH_2Br + AgCN \rightarrow CH_3CH_2NC \] Thus, \[ X = \text{Ethyl isocyanide} \]
Step 3: Reduction of isocyanide On hydrogenation: \[ CH_3CH_2NC + 2H_2 \rightarrow CH_3CH_2NHCH_3 \] This forms: Ethyl methyl amine \[ \boxed{Y=\text{Ethyl methyl amine}} \] Therefore, the correct answer is: \[ \boxed{(D)} \]
Step 2: Reaction with AgCN Alkyl halides with AgCN give isocyanides: \[ CH_3CH_2Br + AgCN \rightarrow CH_3CH_2NC \] Thus, \[ X = \text{Ethyl isocyanide} \]
Step 3: Reduction of isocyanide On hydrogenation: \[ CH_3CH_2NC + 2H_2 \rightarrow CH_3CH_2NHCH_3 \] This forms: Ethyl methyl amine \[ \boxed{Y=\text{Ethyl methyl amine}} \] Therefore, the correct answer is: \[ \boxed{(D)} \]
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