Question

Identify the product obtained when n-Hexane is heated at \(773\) K under \(10\) to \(20\) atm in presence of \(\text{V}_{2}\text{O}_{5}\) ?

• A. \(\text{C}_{6}\text{H}_{12}+\text{H}_{2}\)
• B. \(\text{CH}_{3}\text{-CH}_{2}\text{-CH}_{2}\text{-CH}_{3}+\text{H}_{2}\text{C=CH}_{2}\)
• C. \(\text{C}_{6}\text{H}_{6}+4\text{H}_{2}\)
• D. \(\text{CH}_{3}\text{-CH}_{3}+\text{CH}_{3}\text{-CH}_{2}\text{-CH=CH}_{2}\)

Hint:

Heating n-hexane under pressure with an oxide catalyst causes dehydrogenation and cyclisation to benzene.

Answer 1

The Correct Option is C

Step 1: Understanding the Concept
Alkanes with six or more carbons undergo aromatization on heating with an oxide catalyst under pressure.

Step 2: The Reaction
n-Hexane at 773 K and 10 to 20 atm with \(\text{V}_2\text{O}_5\) undergoes dehydrogenation and cyclisation.

Step 3: Equation
\(\text{C}_6\text{H}_{14}\xrightarrow{\text{V}_2\text{O}_5,\,773\,\text{K}}\text{C}_6\text{H}_6+4\text{H}_2\)

Step 4: Conclusion
Benzene and hydrogen form, option (C).

Final Answer:
The products are benzene and hydrogen. \[ \boxed{\text{(C) }\text{C}_{6}\text{H}_{6}+4\text{H}_{2}} \]