Question:
Identify the product ‘B’ in the following reaction.
\[
\text{2,2-Dichloropropane} \xrightarrow[\Delta]{\text{aq. KOH}} A
\xrightarrow[\text{ii) H}^+]{\text{i) Mg, Benzene}} B
\]
Identify the product ‘B’ in the following reaction.
\[ \text{2,2-Dichloropropane} \xrightarrow[\Delta]{\text{aq. KOH}} A \xrightarrow[\text{ii) H}^+]{\text{i) Mg, Benzene}} B \]
\[ \text{2,2-Dichloropropane} \xrightarrow[\Delta]{\text{aq. KOH}} A \xrightarrow[\text{ii) H}^+]{\text{i) Mg, Benzene}} B \]
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Carbonyl compounds can undergo coupling reactions in presence of magnesium to form diols like pinacol.
Updated On: Feb 11, 2026
- Propanal
- Propanone
- Isopropyl magnesium chloride
- Pinacol
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The Correct Option is D
Solution and Explanation
Step 1: First reaction with aqueous KOH.
2,2-Dichloropropane undergoes hydrolysis with aqueous KOH to form acetone (propanone).
Step 2: Reaction with magnesium in benzene.
Acetone reacts with magnesium to form a Grignard-type intermediate which couples to form a diol.
Step 3: Acidic hydrolysis.
On acidic work-up, the coupled product forms pinacol.
Step 4: Conclusion.
Therefore, the final product B is pinacol.
2,2-Dichloropropane undergoes hydrolysis with aqueous KOH to form acetone (propanone).
Step 2: Reaction with magnesium in benzene.
Acetone reacts with magnesium to form a Grignard-type intermediate which couples to form a diol.
Step 3: Acidic hydrolysis.
On acidic work-up, the coupled product forms pinacol.
Step 4: Conclusion.
Therefore, the final product B is pinacol.
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