Step 1: Determine geometry of \(XeF_4\) and \(PCl_4^+\).
For \(XeF_4\):
\[
AX_4E_2
\]
Geometry is square planar.
For \(PCl_4^+\):
\[
AX_4
\]
Geometry is tetrahedral.
Hence, geometries are different.
Step 2: Determine geometry of \(NH_3\) and \(ClF_3\).
For \(NH_3\):
\[
AX_3E
\]
Geometry is trigonal pyramidal.
For \(ClF_3\):
\[
AX_3E_2
\]
Geometry is T-shaped.
Hence, geometries are different.
Step 3: Determine geometry of \(SF_4\) and \(NH_4^+\).
For \(SF_4\):
\[
AX_4E
\]
Geometry is see-saw.
For \(NH_4^+\):
\[
AX_4
\]
Geometry is tetrahedral.
Hence, geometries are different.
Step 4: Determine geometry of \(XeF_2\) and \(I_3^-\).
For \(XeF_2\):
\[
AX_2E_3
\]
Geometry is linear.
For \(I_3^-\):
\[
AX_2E_3
\]
Geometry is also linear.
Thus, both species have same geometry.
Step 5: Final conclusion.
Hence, the correct pair having same geometry is
\[
\boxed{XeF_2,\ I_3^-}
\]