Step 1: A Lewis acid is a species that can accept an electron pair.
\[
\text{Lewis acid}=\text{electron pair acceptor}
\]
Step 2: \(BF_3\) is a Lewis acid because boron has an incomplete octet and can accept an electron pair.
Step 3: \(H^+\) is also a Lewis acid because it can accept an electron pair from a Lewis base.
\[
H^+ + :NH_3 \rightarrow NH_4^+
\]
Step 4: Now check the other species:
\[
NH_3
\]
has a lone pair on nitrogen, so it acts as a Lewis base, not a Lewis acid.
\[
F^-
\]
also has lone pairs and acts as a Lewis base.
\[
H_2O
\]
can donate lone pairs from oxygen, so it is generally a Lewis base.
Step 5: Therefore, the pair containing only Lewis acids is:
\[
H^+,\ BF_3
\]
\[
\boxed{H^+,\ BF_3}
\]