Question:
Identify the \(P\) and \(Q\) of the following reaction
\[
P+Q\longrightarrow [B(OH)_4]^-+H_3O^+
\]
Identify the \(P\) and \(Q\) of the following reaction
\[ P+Q\longrightarrow [B(OH)_4]^-+H_3O^+ \]
\[ P+Q\longrightarrow [B(OH)_4]^-+H_3O^+ \]
Show Hint
Boric acid is a Lewis acid. It accepts \(OH^-\) from water and forms
\[
[B(OH)_4]^-
\]
along with
\[
H_3O^+
\]
Updated On: Jun 22, 2026
- \(P=H_3BO_3;\;Q=3H_2O\)
- \(P=H_3BO_3;\;Q=2H_2O\)
- \(P=HBO_2;\;Q=2H_2O\)
- \(P=2H_3BO_3;\;Q=H_2O\)
Show Solution
Verified By Collegedunia
The Correct Option is B
Solution and Explanation
Step 1: Identify the nature of boric acid.
Boric acid is \[ H_3BO_3 \] It behaves as a Lewis acid because boron has an incomplete octet and can accept an electron pair from water.
Step 2: Write the reaction of boric acid with water.
Boric acid does not donate a proton directly. Instead, it accepts hydroxide ion from water.
The reaction is \[ H_3BO_3+2H_2O\longrightarrow [B(OH)_4]^-+H_3O^+ \]
Step 3: Compare with the given reaction.
Given reaction is \[ P+Q\longrightarrow [B(OH)_4]^-+H_3O^+ \] Comparing both reactions, we get \[ P=H_3BO_3 \] and \[ Q=2H_2O \]
Step 4: Final conclusion.
Therefore, \[ \boxed{P=H_3BO_3;\;Q=2H_2O} \]
Boric acid is \[ H_3BO_3 \] It behaves as a Lewis acid because boron has an incomplete octet and can accept an electron pair from water.
Step 2: Write the reaction of boric acid with water.
Boric acid does not donate a proton directly. Instead, it accepts hydroxide ion from water.
The reaction is \[ H_3BO_3+2H_2O\longrightarrow [B(OH)_4]^-+H_3O^+ \]
Step 3: Compare with the given reaction.
Given reaction is \[ P+Q\longrightarrow [B(OH)_4]^-+H_3O^+ \] Comparing both reactions, we get \[ P=H_3BO_3 \] and \[ Q=2H_2O \]
Step 4: Final conclusion.
Therefore, \[ \boxed{P=H_3BO_3;\;Q=2H_2O} \]
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