Step 1: Identify the reaction type.
Chlorobenzene reacts with bromine in presence of anhydrous \(FeCl_3\).
This is an electrophilic aromatic substitution reaction.
Step 2: Role of chlorine group.
Chlorine is deactivating due to its \(-I\) effect.
However, due to resonance donation, chlorine directs incoming electrophiles to ortho and para positions.
Thus, bromination gives mainly ortho and para products.
Step 3: Identify the major product.
Among ortho and para products, para product is major because steric hindrance is less at the para position.
Therefore, the major product is:
\[
p\text{-Bromochlorobenzene}
\]
Step 4: Final conclusion.
Hence, the major product formed is
\[
\boxed{p\text{-Bromochlorobenzene}}
\]