Question:

Identify the gate and match \(A, B, Y\) in the bracket to check.

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Treat the second NAND with tied inputs as a NOT gate; NOT after NAND gives AND.
Updated On: Nov 11, 2026
  • \(OR\ (A=1,\ B=1,\ Y=0)\)
  • \(XOR\ (A=0,\ B=0,\ Y=0)\)
  • \(NOT\ (A=1,\ B=1,\ Y=1)\)
  • \(AND\ (A=1,\ B=1,\ Y=1)\)
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The Correct Option is D

Solution and Explanation

The first gate is a NAND gate with inputs \(A\) and \(B\): output \(X=\overline{A\cdot B}\).
The second NAND gate has both its inputs joined to \(X\), so it acts as a NOT gate: \(Y=\overline{X\cdot X}=\overline{X}\).
Hence \(Y=\overline{\overline{A\cdot B}}=A\cdot B\), which is an AND gate.
Check with \(A=1,B=1\): \(X=0\), \(Y=1\). This matches option (4).
Answer: (4) \(AND\ (A=1,\ B=1,\ Y=1)\)
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