Question:
Identify the electrolyte from following so that \(\wedge_0\) is not obtained from the graphical variation of \(\wedge\) against \(\sqrt{\mathrm{C}}\) ?
Identify the electrolyte from following so that \(\wedge_0\) is not obtained from the graphical variation of \(\wedge\) against \(\sqrt{\mathrm{C}}\) ?
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Limiting molar conductivity by extrapolating \(\Lambda\) against \(\sqrt C\) works for strong electrolytes only.
Updated On: Nov 13, 2026
KCl
\(\mathrm{H}_{2}\mathrm{SO}_{4}\)
\(\mathrm{CH}_{3}\mathrm{COOK}\)
\(\mathrm{NH}_{4}\mathrm{OH}\)
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The Correct Option is D
Solution and Explanation
Step 1: Understanding the Concept
For strong electrolytes \(\Lambda\) vs \(\sqrt C\) is nearly a straight line, so extrapolation to zero concentration gives \(\Lambda_0\).
Step 2: Weak electrolytes
For weak electrolytes \(\Lambda\) rises steeply at low concentration, and the graph cannot be extrapolated.
Step 3: Classify
KCl, \(\text{H}_2\text{SO}_4\) and \(\text{CH}_3\text{COOK}\) are strong electrolytes. \(\text{NH}_4\text{OH}\) is a weak base.
Final Answer:
For \(\text{NH}_4\text{OH}\), a weak electrolyte, \(\Lambda_0\) cannot be obtained graphically. \[ \boxed{\text{(D) }\text{NH}_{4}\text{OH}} \]
For strong electrolytes \(\Lambda\) vs \(\sqrt C\) is nearly a straight line, so extrapolation to zero concentration gives \(\Lambda_0\).
Step 2: Weak electrolytes
For weak electrolytes \(\Lambda\) rises steeply at low concentration, and the graph cannot be extrapolated.
Step 3: Classify
KCl, \(\text{H}_2\text{SO}_4\) and \(\text{CH}_3\text{COOK}\) are strong electrolytes. \(\text{NH}_4\text{OH}\) is a weak base.
Final Answer:
For \(\text{NH}_4\text{OH}\), a weak electrolyte, \(\Lambda_0\) cannot be obtained graphically. \[ \boxed{\text{(D) }\text{NH}_{4}\text{OH}} \]
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