Question:
Identify the correct increasing order of boiling point of following compounds.
Identify the correct increasing order of boiling point of following compounds.
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More Br atoms → higher mass → higher boiling point.
Updated On: May 4, 2026
- \(\text{CHBr}_3 < \text{CH}_2\text{Br}_2 < \text{CH}_3\text{Br} < \text{CH}_3\text{Cl}\)
- \(\text{CH}_3\text{Cl} < \text{CH}_3\text{Br} < \text{CH}_2\text{Br}_2 < \text{CHBr}_3\)
- \(\text{CH}_3\text{Br} < \text{CH}_2\text{Br}_2 < \text{CHBr}_3 < \text{CH}_3\text{Cl}\)
- \(\text{CH}_2\text{Br}_2 < \text{CHBr}_3 < \text{CH}_3\text{Br} < \text{CH}_3\text{Cl}\)
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The Correct Option is B
Solution and Explanation
Concept:
Boiling point increases with:
• Molecular mass
• Polarizability
Step 1: Compare compounds.
• CH$_3$Cl → lowest mass
• CH$_3$Br → higher
• CH$_2$Br$_2$ → more mass
• CHBr$_3$ → highest mass
Step 2: Order. \[ \text{CH}_3\text{Cl} < \text{CH}_3\text{Br} < \text{CH}_2\text{Br}_2 < \text{CHBr}_3 \]
Step 3: Conclusion. \[ \text{Correct answer = Option (B)} \]
Boiling point increases with:
• Molecular mass
• Polarizability
Step 1: Compare compounds.
• CH$_3$Cl → lowest mass
• CH$_3$Br → higher
• CH$_2$Br$_2$ → more mass
• CHBr$_3$ → highest mass
Step 2: Order. \[ \text{CH}_3\text{Cl} < \text{CH}_3\text{Br} < \text{CH}_2\text{Br}_2 < \text{CHBr}_3 \]
Step 3: Conclusion. \[ \text{Correct answer = Option (B)} \]
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