Question:
Identify the compound from following so that Ostwald's dilution law is NOT applicable to it.
Identify the compound from following so that Ostwald's dilution law is NOT applicable to it.
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Ostwald's dilution law is valid only for weak electrolytes, so choose the strong electrolyte.
Updated On: Nov 13, 2026
NaOH
\(\mathrm{NH}_{4}\mathrm{OH}\)
\(\mathrm{H}_{2}\mathrm{CO}_{3}\)
\(\mathrm{H}_{2}\text{ }\mathrm{S}\)
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The Correct Option is A
Solution and Explanation
Step 1: Understanding the Concept
Ostwald's dilution law \(K=\dfrac{C\alpha^2}{1-\alpha}\) applies to weak electrolytes that are partially ionised.
Step 2: Classify
\(\text{NH}_4\text{OH}\), \(\text{H}_2\text{CO}_3\), \(\text{H}_2\text{S}\) are weak electrolytes.\nNaOH is a strong base and ionises completely.
Final Answer:
NaOH, a strong electrolyte, does not obey Ostwald's dilution law. \[ \boxed{\text{(A) }\text{NaOH}} \]
Ostwald's dilution law \(K=\dfrac{C\alpha^2}{1-\alpha}\) applies to weak electrolytes that are partially ionised.
Step 2: Classify
\(\text{NH}_4\text{OH}\), \(\text{H}_2\text{CO}_3\), \(\text{H}_2\text{S}\) are weak electrolytes.\nNaOH is a strong base and ionises completely.
Final Answer:
NaOH, a strong electrolyte, does not obey Ostwald's dilution law. \[ \boxed{\text{(A) }\text{NaOH}} \]
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