Question:

Identify product P in following reaction. Acetamide \(+4[\mathrm{H}] \xrightarrow{\mathrm{Na}_2-\mathrm{C}_2 \mathrm{H}_5 \mathrm{OH}} \mathrm{P}\)

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Reduction of an amide with \(\text{Na/C}_2\text{H}_5\text{OH}\) gives the amine with the same number of carbon atoms.
Updated On: Nov 13, 2026
  • Methanamine

  • Acetonitrile

  • Ethanamine

  • Ethanoic acid

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The Correct Option is C

Solution and Explanation

Step 1: Understanding the Concept
Amides are reduced by nascent hydrogen (Na with alcohol) to primary amines with the same carbon skeleton.

Step 2: Reaction
\(\text{CH}_3\text{CONH}_2+4[\text{H}]\xrightarrow{\text{Na/C}_2\text{H}_5\text{OH}}\text{CH}_3\text{CH}_2\text{NH}_2+\text{H}_2\text{O}\).

Step 3: Name
\(\text{CH}_3\text{CH}_2\text{NH}_2\) is ethanamine.

Final Answer:
Product P is ethanamine. \[ \boxed{\text{(C) }\text{Ethanamine}} \]
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