Question:
Identify product ' $B$ ' in the following sequence of reaction.
$\text{Aniline} \xrightarrow[273 \text{ K}]{\text{NaNO}_2 + \text{HCl}} \text{A} \xrightarrow{\Delta}{\text{H}_2\text{O}} \text{B} + \text{N}_2 \uparrow$
Identify product ' $B$ ' in the following sequence of reaction.
$\text{Aniline} \xrightarrow[273 \text{ K}]{\text{NaNO}_2 + \text{HCl}} \text{A} \xrightarrow{\Delta}{\text{H}_2\text{O}} \text{B} + \text{N}_2 \uparrow$
$\text{Aniline} \xrightarrow[273 \text{ K}]{\text{NaNO}_2 + \text{HCl}} \text{A} \xrightarrow{\Delta}{\text{H}_2\text{O}} \text{B} + \text{N}_2 \uparrow$
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Warming diazonium salts with water is the standard laboratory method to prepare phenols.
Updated On: Apr 26, 2026
- Sodium phenoxide
- Nitrobenzene
- Benzenediazonium chloride
- Phenol
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The Correct Option is D
Solution and Explanation
Step 1: Diazotization
Aniline reacts with $\text{NaNO}_2 + \text{HCl}$ at $273-278\text{ K}$ to form Benzenediazonium chloride (Product 'A').
Step 2: Hydrolysis
When an aqueous solution of Benzenediazonium chloride is warmed ($\Delta$), it undergoes hydrolysis.
Step 3: Conclusion
The reaction is: $C_6H_5N_2Cl + H_2O \to C_6H_5OH + N_2 + HCl$. Product 'B' is Phenol.
Final Answer: (D)
Aniline reacts with $\text{NaNO}_2 + \text{HCl}$ at $273-278\text{ K}$ to form Benzenediazonium chloride (Product 'A').
Step 2: Hydrolysis
When an aqueous solution of Benzenediazonium chloride is warmed ($\Delta$), it undergoes hydrolysis.
Step 3: Conclusion
The reaction is: $C_6H_5N_2Cl + H_2O \to C_6H_5OH + N_2 + HCl$. Product 'B' is Phenol.
Final Answer: (D)
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