Question:
Identify from the following the pair of solutions which on mixing exhibits positive deviation from Raoult's law.
Identify from the following the pair of solutions which on mixing exhibits positive deviation from Raoult's law.
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Positive deviation occurs when the unlike attractions are weaker than the like attractions.
Updated On: Nov 12, 2026
- Chloroform and acetone
- Carbon disulfide and acetone
- Phenol and aniline
- Benzene and toluene
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The Correct Option is B
Solution and Explanation
Step 1: Understanding the Concept
Positive deviation from Raoult's law occurs when A-B attractions are weaker than A-A and B-B attractions, so the vapour pressure is higher than expected.
Step 2: Check each pair
Chloroform and acetone: hydrogen bonding forms between them, giving negative deviation.
Phenol and aniline: O-H...N hydrogen bonding, negative deviation.
Benzene and toluene: very similar molecules, nearly ideal.
Step 3: The pair with positive deviation
Non-polar carbon disulfide breaks up the dipole-dipole attractions of acetone and gives only weak attractions in return. This gives positive deviation.
Final Answer:
Carbon disulfide and acetone show positive deviation. \[ \boxed{\text{(B) }\text{Carbon disulfide and acetone}} \]
Positive deviation from Raoult's law occurs when A-B attractions are weaker than A-A and B-B attractions, so the vapour pressure is higher than expected.
Step 2: Check each pair
Chloroform and acetone: hydrogen bonding forms between them, giving negative deviation.
Phenol and aniline: O-H...N hydrogen bonding, negative deviation.
Benzene and toluene: very similar molecules, nearly ideal.
Step 3: The pair with positive deviation
Non-polar carbon disulfide breaks up the dipole-dipole attractions of acetone and gives only weak attractions in return. This gives positive deviation.
Final Answer:
Carbon disulfide and acetone show positive deviation. \[ \boxed{\text{(B) }\text{Carbon disulfide and acetone}} \]
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