Question

Identify from following compounds where valence shell of 'Xe' consists one lone pair of electrons.

• A. \(\mathrm{XeF}_{2}\)
• B. \(\mathrm{XeF}_{4}\)
• C. \(\mathrm{XeOF}_{2}\)
• D. \(\mathrm{XeOF}_{4}\)

Hint:

Count the valence electrons of xenon, subtract those used in bonds, and divide the remainder by two.

Answer 1

The Correct Option is D

Step 1: Understanding the Concept
Xe has 8 valence electrons.
Lone pairs on Xe \(=\dfrac{8-\text{electrons used in bonds}}{2}\).

Step 2: Count for each compound
\(\text{XeF}_2\): 2 bonds, so 3 lone pairs.
\(\text{XeF}_4\): 4 bonds, so 2 lone pairs.
\(\text{XeOF}_2\): 2 Xe-F bonds and 1 Xe=O bond use 4 electrons, so 2 lone pairs.
\(\text{XeOF}_4\): 4 Xe-F bonds and 1 Xe=O bond use 6 electrons, so 1 lone pair.

Step 3: Conclusion
Only \(\text{XeOF}_4\) has one lone pair on Xe (square pyramidal shape).

Final Answer:
\(\text{XeOF}_4\) has one lone pair on xenon. \[ \boxed{\text{(D) }\text{XeOF}_{4}} \]