Question:

Identify conjugate acid and conjugate base for \( HCO_3^- \) ion respectively:

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Remember: \[ \text{Conjugate Acid} = \text{Species} + H^+ \] \[ \text{Conjugate Base} = \text{Species} - H^+ \] Always carefully check the charge after adding or removing a proton.
Updated On: May 19, 2026
  • Carbonic acid and carbonate ion
  • Carbonate ion and carbonic acid
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  • Water and carbon dioxide
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The Correct Option is A

Solution and Explanation

Concept: According to the Brønsted-Lowry acid-base theory:
• A conjugate acid is formed when a species accepts a proton (\(H^+\)).
• A conjugate base is formed when a species donates a proton (\(H^+\)). The ion \( HCO_3^- \) is called the bicarbonate ion and is an amphiprotic species, which means it can behave both as an acid and as a base depending upon the reaction conditions.

Step 1:
Finding the conjugate acid of \( HCO_3^- \).
To obtain the conjugate acid, the given species must accept one proton (\(H^+\)). \[ HCO_3^- + H^+ \rightarrow H_2CO_3 \] Here, the bicarbonate ion gains one proton and forms carbonic acid. Therefore, the conjugate acid of \( HCO_3^- \) is: \[ H_2CO_3 \]

Step 2:
Finding the conjugate base of \( HCO_3^- \).
To obtain the conjugate base, the given species must donate one proton (\(H^+\)). \[ HCO_3^- \rightarrow H^+ + CO_3^{2-} \] After losing one proton, bicarbonate ion forms carbonate ion. Therefore, the conjugate base of \( HCO_3^- \) is: \[ CO_3^{2-} \]

Step 3:
Matching with the given options.
From the above calculations: \[ \text{Conjugate Acid} = H_2CO_3 \] \[ \text{Conjugate Base} = CO_3^{2-} \] Hence, the correct pair is: \[ H_2CO_3 \text{ and } CO_3^{2-} \]

Step 4:
Evaluation of the given options.}
• \( CO_3^{2-} \) and \( H_2CO_3 \): Incorrect order.
• \( H_2CO_3 \) and \( CO_2 \): Incorrect because \( CO_2 \) is not the conjugate base.
• \( CO_2 \) and \( H_2CO_3 \): Incorrect pair.
• \( H_2CO_3 \) and \( CO_3^{2-} \): Correct pair.
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