Question:
Identify a molecule having octahedral geometry as per VSEPR theory.
Identify a molecule having octahedral geometry as per VSEPR theory.
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6 bond pairs → Octahedral geometry.
Updated On: May 4, 2026
- \(\text{PCl}_5\)
- \(\text{CH}_4\)
- \(\text{BeCl}_2\)
- \(\text{SF}_6\)
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The Correct Option is D
Solution and Explanation
Concept:
VSEPR theory → geometry depends on number of bond pairs.
Step 1: Count bond pairs.
• PCl$_5$ → 5 pairs → trigonal bipyramidal
• CH$_4$ → 4 pairs → tetrahedral
• BeCl$_2$ → 2 pairs → linear
• SF$_6$ → 6 pairs → octahedral Conclusion: \[ \text{Octahedral geometry = SF}_6 \]
VSEPR theory → geometry depends on number of bond pairs.
Step 1: Count bond pairs.
• PCl$_5$ → 5 pairs → trigonal bipyramidal
• CH$_4$ → 4 pairs → tetrahedral
• BeCl$_2$ → 2 pairs → linear
• SF$_6$ → 6 pairs → octahedral Conclusion: \[ \text{Octahedral geometry = SF}_6 \]
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