
To identify A, B, and C in the given reaction sequence, let's analyze each step:
Reaction with A: The initial compound contains an alkene group. When alkenes react with bromine \((\text{Br}_2)\), an anti-addition reaction occurs, leading to vicinal dibromides. Hence, A = Br2.
Reaction with B: The dibromide undergoes dehydrohalogenation. With alcoholic KOH, elimination occurs, forming an alkyne. Therefore, B = KOH.
Reaction with C: The alkyne can undergo further deprotonation when reacted with sodium amide \((\text{NaNH}_2)\) to form a more reactive acetylide ion. Thus, C = NaNH2.
Therefore, the correct sequence is: A=Br2, B=KOH, C=NaNH2.
List I | List II | ||
|---|---|---|---|
| A | \(\Omega^{-1}\) | I | Specific conductance |
| B | \(∧\) | II | Electrical conductance |
| C | k | III | Specific resistance |
| D | \(\rho\) | IV | Equivalent conductance |
List I | List II | ||
|---|---|---|---|
| A | Constant heat (q = 0) | I | Isothermal |
| B | Reversible process at constant temperature (dT = 0) | II | Isometric |
| C | Constant volume (dV = 0) | III | Adiabatic |
| D | Constant pressure (dP = 0) | IV | Isobar |