Question:
Hydrolysis of sucrose gives
Hydrolysis of sucrose gives
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Sucrose is a non-reducing sugar but hydrolysis produces reducing sugars glucose and fructose.
Updated On: Jun 20, 2026
- Dextorotatory glucose & Laevorotatory fructose
- Dextorotatory fructose & Laevorotatory glucose
- Dextorotatory glucose & Dextorotatory fructose
- Laevorotatory glucose & Laevorotatory fructose
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The Correct Option is A
Solution and Explanation
Step 1: Understand sucrose hydrolysis.
Sucrose is a disaccharide composed of glucose and fructose linked via glycosidic bond. On hydrolysis (acid or enzyme), it breaks into equimolar glucose and fructose.
Step 2: Identify products formed.
Hydrolysis reaction: \[ \text{sucrose} + H_2O \rightarrow \text{glucose} + \text{fructose} \] Thus the products are glucose and fructose.
Step 3: Optical rotation of glucose.
Glucose is dextrorotatory, meaning it rotates plane-polarized light to the right (positive rotation).
Step 4: Optical rotation of fructose.
Fructose is laevorotatory, meaning it rotates plane-polarized light to the left (negative rotation), even though it is sweeter than glucose.
Step 5: Final product identification.
Therefore hydrolysis of sucrose produces: - D-glucose (dextrorotatory) - D-fructose (laevorotatory)
Step 6: Final conclusion.
Hence correct pair is dextrorotatory glucose and laevorotatory fructose.
Final Answer: \[ \boxed{\text{D-glucose and D-fructose (as given in option 1)}} \]
Sucrose is a disaccharide composed of glucose and fructose linked via glycosidic bond. On hydrolysis (acid or enzyme), it breaks into equimolar glucose and fructose.
Step 2: Identify products formed.
Hydrolysis reaction: \[ \text{sucrose} + H_2O \rightarrow \text{glucose} + \text{fructose} \] Thus the products are glucose and fructose.
Step 3: Optical rotation of glucose.
Glucose is dextrorotatory, meaning it rotates plane-polarized light to the right (positive rotation).
Step 4: Optical rotation of fructose.
Fructose is laevorotatory, meaning it rotates plane-polarized light to the left (negative rotation), even though it is sweeter than glucose.
Step 5: Final product identification.
Therefore hydrolysis of sucrose produces: - D-glucose (dextrorotatory) - D-fructose (laevorotatory)
Step 6: Final conclusion.
Hence correct pair is dextrorotatory glucose and laevorotatory fructose.
Final Answer: \[ \boxed{\text{D-glucose and D-fructose (as given in option 1)}} \]
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