Question:

Hybridisation of carbon in CH$_3^-$

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Count lone pair on carbon in negative ions carefully.
Updated On: May 1, 2026
  • sp$^2$
  • sp$^3$
  • sp$^3$d
  • sp$^3$d$^2$
  • sp$^2$d$^3$
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The Correct Option is B

Solution and Explanation


Concept:
Hybridisation depends on steric number: \[ \text{Steric number} = \text{bond pairs} + \text{lone pairs} \]

Step 1:
Structure of CH$_3^-$.
Carbon forms 3 bonds with H and has 1 lone pair. \[ \text{Steric number} = 3 + 1 = 4 \]

Step 2:
Hybridisation.
Steric number 4 → sp$^3$

Step 3:
Geometry.
Trigonal pyramidal shape.
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