Question:
How many litres of O\(_2\) at 273 K and 1 atm pressure can give 20 L of CO in the following reaction?
\[
C + O_2 \rightarrow CO_2 \rightarrow CO
\]
How many litres of O\(_2\) at 273 K and 1 atm pressure can give 20 L of CO in the following reaction?
\[ C + O_2 \rightarrow CO_2 \rightarrow CO \]
\[ C + O_2 \rightarrow CO_2 \rightarrow CO \]
Show Hint
At STP, volume ratios of gases are directly proportional to mole ratios in the balanced chemical equation.
Updated On: Jun 19, 2026
- 40 L
- 20 L
- 5 L
- 10 L
Show Solution
Verified By Collegedunia
The Correct Option is D
Solution and Explanation
Step 1: Understanding the reaction pathway.
Carbon reacts with oxygen to form carbon dioxide, and under reducing conditions carbon dioxide further converts to carbon monoxide. The net reaction for CO formation is effectively: \[ 2C + O_2 \rightarrow 2CO \]
This shows the stoichiometric relation between oxygen and carbon monoxide.
Step 2: Establishing mole ratio.
From the balanced equation, 1 mole of O\(_2\) produces 2 moles of CO. This means volume ratio at STP is also: \[ 1 \text{ volume O}_2 \rightarrow 2 \text{ volumes CO} \]
Step 3: Using given CO volume.
Given CO produced = 20 L. Using the ratio, oxygen required will be half of CO volume because 1:2 relation exists.
Step 4: Calculating oxygen volume.
\[ V_{O_2} = \frac{20}{2} = 10 \text{ L} \]
Thus, 10 L of oxygen is required under given conditions.
Step 5: Final verification.
Since conditions are 273 K and 1 atm (STP), volume ratios directly follow mole ratios, confirming correctness of result.
Final Answer: \[ \boxed{10 \text{ L}} \]
Carbon reacts with oxygen to form carbon dioxide, and under reducing conditions carbon dioxide further converts to carbon monoxide. The net reaction for CO formation is effectively: \[ 2C + O_2 \rightarrow 2CO \]
This shows the stoichiometric relation between oxygen and carbon monoxide.
Step 2: Establishing mole ratio.
From the balanced equation, 1 mole of O\(_2\) produces 2 moles of CO. This means volume ratio at STP is also: \[ 1 \text{ volume O}_2 \rightarrow 2 \text{ volumes CO} \]
Step 3: Using given CO volume.
Given CO produced = 20 L. Using the ratio, oxygen required will be half of CO volume because 1:2 relation exists.
Step 4: Calculating oxygen volume.
\[ V_{O_2} = \frac{20}{2} = 10 \text{ L} \]
Thus, 10 L of oxygen is required under given conditions.
Step 5: Final verification.
Since conditions are 273 K and 1 atm (STP), volume ratios directly follow mole ratios, confirming correctness of result.
Final Answer: \[ \boxed{10 \text{ L}} \]
Was this answer helpful?
0
0
Top AP EAPCET Chemistry Questions
- The four quantum numbers of the valence electron of potassium are :
- The volume of $0.02\, M$ acidified permanganate solution required for complete reaction of $60\, mL$ of $0.01\, MI^{-}$ ion solution to form $I_2$ in $mL$ is
- In which of the following the election gain enthalpy of elements is correctly arranged?
- The radii of $ \text{F,}{{\text{F}}^{-}}\text{O} $ and $ {{\text{O}}^{2-}} $ are in the order
- Which of the following has the highest first ionization potential?
View More Questions
Top AP EAPCET Laws of Chemical Combinations Questions
Top AP EAPCET Questions
- A body is projected from the ground at an angle of $\tan^{-1} \left( \frac{8}{7}\right)$ with the horizontal. The ratio of the maximum height attained by it to its range is
- The four quantum numbers of the valence electron of potassium are :
- A lens forms real and virtual images of an object, when the object is at $u_{1}$ and $u_{2}$ distances respectively. If the size of the virtual image is double that of the real image, then the focal length of the lens is (take, the magnification of the real image as $m$ )
- Two spheres $P$ and $Q$, each of mass $200\, g$ are attached to a string of length one metre as shown in the figure. The string and the spheres are then whirled in a horizontal circle about $O$ at a constant angular speed. The ratio of the tension in the string between $P$ and $Q$ to that of between $P$ and $O$ is $(P$ is at mid-point of the line joining $O$ and $Q$ )
- The volume of $0.02\, M$ acidified permanganate solution required for complete reaction of $60\, mL$ of $0.01\, MI^{-}$ ion solution to form $I_2$ in $mL$ is
View More Questions