Step 1: Understanding the Concept
In glycolysis, one 6-carbon glucose molecule is split into two 3-carbon pyruvic acid molecules.
Step 2: Calculation
Glucose used \(= \dfrac{\text{pyruvic acid formed}}{2} = \dfrac{68}{2} = 34\).
Step 3: Compare the options
The value 34 matches option (B). The values 17 and 51 do not fit the 1 : 2 ratio, and 68 would be correct only if one glucose gave one pyruvic acid.
Final Answer:
34 glucose molecules are used.
\[ \boxed{\text{(B) }34} \]