Question

The number of reduced coenzymes $\text{NADH} + \text{H}^{+}$ formed during complete oxidation of one molecule of glucose.

• A. $2$
• B. $8$
• C. $10$
• D. $12$

Hint:

Shortcut: Glycolysis (2) + Link (2) + Krebs (6) = 10 NADH

Answer 1

The Correct Option is C

Concept: Complete oxidation of glucose occurs in three stages:
• Glycolysis
• Link reaction (pyruvate oxidation)
• Krebs cycle

Step 1: NADH from glycolysis.
Each glucose produces 2 NADH.

Step 2: NADH from link reaction.
Each glucose (2 pyruvate) produces 2 NADH.

Step 3: NADH from Krebs cycle.
Each acetyl Co-A produces 3 NADH. Since 2 acetyl Co-A are formed: $3 \times 2 = 6$ NADH

Step 4: Total NADH.
\[ 2 + 2 + 6 = 10 \text{ NADH} \]

Step 5: Conclusion.
Thus, 10 NADH molecules are formed. Final Answer: Option (C)