Question:
How many different nine digit numbers can be formed from the number 223355888 by rearranging its digits so that odd digits occupy even positions?
How many different nine digit numbers can be formed from the number 223355888 by rearranging its digits so that odd digits occupy even positions?
Show Hint
Handle odd and even positions separately, then multiply.
Updated On: Mar 20, 2026
- 16
- 36
- 60
- 180
Show Solution
Verified By Collegedunia
The Correct Option is D
Solution and Explanation
Odd digits: 3,3,5,5 (4 digits)
Even positions: 4 places
Arrangements of odd digits:
(4!)/(2!2!)=6
Even digits: 2,2,8,8,8 (5 digits)
Odd positions: 5 places
Arrangements:
(5!)/(2!3!)=10
Total numbers:
6× 10=60
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