Question:
How many atoms are present in 1 mole of oxygen gas (O2)?
How many atoms are present in 1 mole of oxygen gas (O2)?
Updated On: Mar 18, 2026
- \( 6.022 \times 10^{23} \)
- \( 1.204 \times 10^{24} \)
- \( 3.011 \times 10^{23} \)
- \( 2 \times 6.022 \times 10^{23} \)
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The Correct Option is B
Solution and Explanation
Step 1: Know that 1 mole of any gas contains 6.022 × 1023 molecules.
Step 2: Oxygen gas (O2) is diatomic, so 1 molecule contains 2 atoms.
Therefore, total atoms = 2 × 6.022 × 1023 = 1.204 × 1024 atoms
Answer: 1.204 × 1024 atoms
Step 2: Oxygen gas (O2) is diatomic, so 1 molecule contains 2 atoms.
Therefore, total atoms = 2 × 6.022 × 1023 = 1.204 × 1024 atoms
Answer: 1.204 × 1024 atoms
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