Homing pigeons rely on their biological clock and the position of the sun for navigation. The direction they fly depends on their internal clock and how it aligns with the time of day at their release site.
Bird N is the normal bird, whose biological clock is not adjusted. Therefore, it perceives 6 AM as the natural time of release and will use the sun's position accordingly. Since the bird is 30 km East of its home, it will orient West towards its home.
Bird C has been clock-adjusted by 12 hours. This means it perceives the 6 AM release time as 6 PM and uses the sun's position as if it were the evening. Since it is 30 km East, the bird will attempt to fly East, as it mistakenly perceives the sun's position as evening and moves away from its home.
Thus, the correct answer is (C), where Bird N flies West and Bird C flies East.