Question:

Heterocyclic ring present in acetazolamide is

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Acetazolamide = Thia (Sulfur) + Dia (Two Nitrogens) + Azole (Ring).
  • Thiophene
  • Thiazole
  • Thiadiazole
  • Oxathiazole
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The Correct Option is C

Solution and Explanation

Step 1: Concept
Acetazolamide is a carbonic anhydrase inhibitor used as a diuretic and for treating glaucoma.

Step 2: Meaning

Its chemical structure includes a five-membered heterocyclic ring containing both nitrogen and sulfur.

Step 3: Analysis

The chemical name of acetazolamide is N-(5-sulfamoyl-1,3,4-thiadiazol-2-yl)acetamide. This confirms the presence of the thiadiazole ring.

Step 4: Conclusion

Thus, the heterocyclic core of acetazolamide is a thiadiazole ring.

Final Answer: (C)
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