Question:

Given that 1 g of water in liquid phase has volume 1 cm\(^3\) and in vapour phase 1671 cm\(^3\) at atmospheric pressure and the latent heat of vaporization of water is 2256 J/g; the change in the internal energy in joules for 1 g of water at 373 K when it changes from liquid phase to vapour phase at the same temperature is :

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First law: \(\Delta U=Q-W\), with \(Q=mL\) and \(W=P\,\Delta V\) at atmospheric pressure.
Updated On: Oct 31, 2026
  • 2256
  • 167
  • 2089
  • 1
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The Correct Option is C

Solution and Explanation

Heat absorbed \(Q=mL=1\times2256=2256\) J.
Work done by the water on expansion: \(W=P\,\Delta V\) with \(P=1.013\times10^5\) Pa and \(\Delta V=(1671-1)\ \mathrm{cm^3}=1670\times10^{-6}\ \mathrm{m^3}\).
\(W=1.013\times10^5\times1.67\times10^{-3}\approx169\) J (about 167 J as in the data).
\(\Delta U=Q-W=2256-167\approx2089\) J.
Answer: (3) 2089
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