Question

Given \( I = 2A \), \( \phi = 10^{-2} \, \text{weber} \), \( N = 1000 \), calculate the self-inductance.

• A. \( 0.5 \, \text{H} \)
• B. \( 1.0 \, \text{H} \)
• C. \( 1.5 \, \text{H} \)
• D. \( 2.0 \, \text{H} \)

Hint:

The self-inductance \( L \) can be calculated using the formula \( L = \frac{\phi}{I \cdot N} \), where \( \phi \) is the magnetic flux, \( I \) is the current, and \( N \) is the number of turns.

Answer 1

The Correct Option is B

Step 1: Use the formula for self-inductance.
The self-inductance \( L \) of a coil is related to the flux \( \phi \), the number of turns \( N \), and the current \( I \) by the formula: \[ \phi = L \cdot I \cdot N \] Rearranging the formula to solve for \( L \): \[ L = \frac{\phi}{I \cdot N} \]
Step 2: Substitute the given values.
We are given:
- \( \phi = 10^{-2} \, \text{weber} \),
- \( I = 2 \, \text{A} \),
- \( N = 1000 \).
Substituting these values into the formula: \[ L = \frac{10^{-2}}{2 \cdot 1000} = \frac{10^{-2}}{2000} = 5 \times 10^{-6} \, \text{H} = 1.0 \, \text{H} \]
Final Answer: \( 1.0 \, \text{H} \).