Question:
Given below are two statements:
Statement I: Sucrose consists of \(\alpha\)-D-glucose and \(\beta\)-D-fructose units.
Statement II: Lactose consists of \(\beta\)-D-galactose and \(\beta\)-D-glucose units.
Given below are two statements:
Statement I: Sucrose consists of \(\alpha\)-D-glucose and \(\beta\)-D-fructose units.
Statement II: Lactose consists of \(\beta\)-D-galactose and \(\beta\)-D-glucose units.
Show Hint
Remember:
\[
\text{Sucrose} = \text{Glucose + Fructose}
\]
\[
\text{Lactose} = \text{Galactose + Glucose}
\]
\[
\text{Maltose} = \text{Glucose + Glucose}
\]
Updated On: Jun 10, 2026
- Both Statement I and Statement II are correct.
- Statement I is correct but Statement II is incorrect.
- Statement I is incorrect but Statement II is correct.
- Both Statement I and Statement II are incorrect.
Show Solution
Verified By Collegedunia
The Correct Option is A
Solution and Explanation
Concept:
Disaccharides are carbohydrates formed by the condensation of two monosaccharide units through glycosidic linkage.
Different disaccharides contain different combinations of monosaccharides.
Step 1: Analyse Statement I Sucrose is composed of: \[ \alpha\text{-D-glucose} \] and \[ \beta\text{-D-fructose} \] linked through \[ \alpha(1\rightarrow2)\beta \] glycosidic bond. Hence Statement I is correct. \[ \boxed{\text{Statement I is correct}} \]
Step 2: Analyse Statement II Lactose is composed of: \[ \beta\text{-D-galactose} \] and \[ \beta\text{-D-glucose} \] linked through a \[ \beta(1\rightarrow4) \] glycosidic linkage. Therefore Statement II is also correct. \[ \boxed{\text{Statement II is correct}} \]
Final Conclusion Since both statements are correct, \[ \boxed{\text{Option (A)}} \]
Step 1: Analyse Statement I Sucrose is composed of: \[ \alpha\text{-D-glucose} \] and \[ \beta\text{-D-fructose} \] linked through \[ \alpha(1\rightarrow2)\beta \] glycosidic bond. Hence Statement I is correct. \[ \boxed{\text{Statement I is correct}} \]
Step 2: Analyse Statement II Lactose is composed of: \[ \beta\text{-D-galactose} \] and \[ \beta\text{-D-glucose} \] linked through a \[ \beta(1\rightarrow4) \] glycosidic linkage. Therefore Statement II is also correct. \[ \boxed{\text{Statement II is correct}} \]
Final Conclusion Since both statements are correct, \[ \boxed{\text{Option (A)}} \]
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