Step 1: Statement I
Above the surface, \(g\) falls as \(\frac{1}{r^2}\). Below the surface, \(g=g_0\frac{r}{R}\) falls linearly to zero at the centre. \(g\) is greatest at the surface. So statement I is correct.
Step 2: Statement II
For small \(h\): \(g_h=g\left(1-\frac{2h}{R}\right)\). For small \(d\): \(g_d=g\left(1-\frac{d}{R}\right)\).
Setting \(h=d\) gives different values. They are equal only when \(d=2h\). So statement II is incorrect.
Step 3: Result
Statement I is correct and II is incorrect. Option (C).
Final Answer:
Statement I is correct, II is incorrect, option (C).
\[ \boxed{\text{(C)}} \]