Question:
Fraction decayed in 6 days is \(7/8\). Find fraction decayed in 10 days.
Fraction decayed in 6 days is \(7/8\). Find fraction decayed in 10 days.
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Use exponential decay: \(N = N_0 e^{-\lambda t}\).
Updated On: Apr 23, 2026
- \(77/80\)
- \(71/80\)
- \(31/32\)
- \(15/16\)
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Verified By Collegedunia
The Correct Option is C
Solution and Explanation
Step 1: Remaining after 6 days
\[
= 1 - \frac{7}{8} = \frac{1}{8}
\]
Step 2: After 10 days \[ \left(\frac{1}{8}\right)^{10/6} = \left(\frac{1}{2}\right)^5 = \frac{1}{32} \]
Step 3: Decayed fraction \[ = 1 - \frac{1}{32} = \frac{31}{32} \]
Step 2: After 10 days \[ \left(\frac{1}{8}\right)^{10/6} = \left(\frac{1}{2}\right)^5 = \frac{1}{32} \]
Step 3: Decayed fraction \[ = 1 - \frac{1}{32} = \frac{31}{32} \]
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