Question:

\( \frac{\sin A - \sin B}{\cos A + \cos B} \) is equal to

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Always convert sums/differences into product form before simplifying.
Updated On: May 1, 2026
  • \( \sin\frac{A+B}{2} \)
  • \( 2\tan(A+B) \)
  • \( \cot\frac{A-B}{2} \)
  • \( \tan\frac{A-B}{2} \)
  • \( 2\cot(A+B) \)
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The Correct Option is D

Solution and Explanation

Concept: Use sum-to-product identities.

Step 1:
Use identity: \[ \sin A - \sin B = 2\cos\frac{A+B}{2}\sin\frac{A-B}{2} \]

Step 2:
Use identity: \[ \cos A + \cos B = 2\cos\frac{A+B}{2}\cos\frac{A-B}{2} \]

Step 3:
Substitute into expression.

Step 4:
Cancel common term: \[ 2\cos\frac{A+B}{2} \]

Step 5:
Result: \[ \frac{\sin\frac{A-B}{2}}{\cos\frac{A-B}{2}} = \tan\frac{A-B}{2} \]
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