Question:

If \( f(x) = \tan^{-1}\left(\frac{2x}{1 - x^2}\right) \), then \( f\left(\frac{1}{\sqrt{3}}\right) \) is equal to

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Memorize: \( \tan^{-1}\left(\frac{2x}{1-x^2}\right)=2\tan^{-1}x \) for quick solving.
Updated On: Apr 21, 2026
  • \( \frac{\pi}{6} \)
  • \( \frac{2\pi}{3} \)
  • \( \frac{\pi}{3} \)
  • \( \frac{4\pi}{3} \)
  • \( 0 \)
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The Correct Option is C

Solution and Explanation

Concept: \[ \tan^{-1}\left(\frac{2x}{1-x^2}\right) = 2\tan^{-1}x \]

Step 1:
Apply identity.
\[ f(x) = 2\tan^{-1}x \]

Step 2:
Substitute value.
\[ f\left(\frac{1}{\sqrt{3}}\right) = 2\tan^{-1}\left(\frac{1}{\sqrt{3}}\right) \] \[ = 2 \cdot \frac{\pi}{6} = \frac{\pi}{3} \]
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