Question:
Four ideal diodes are connected as shown then the current drawn from the battery is
Four ideal diodes are connected as shown then the current drawn from the battery is
Show Hint
For diode circuits:
- Identify conducting path first
- Replace forward diodes with wire, reverse with open
Updated On: Apr 30, 2026
- zero
- $10$ mA
- $100$ mA
- $50$ mA
- $20$ mA
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The Correct Option is B
Solution and Explanation
Concept:
For ideal diodes:
• Forward biased $\rightarrow$ acts as short circuit
• Reverse biased $\rightarrow$ acts as open circuit
Step 1: Analyze diode directions.
From the circuit: - Only one conducting path is available due to diode orientations.
Step 2: Equivalent circuit.
Effective resistance in the conducting path: \[ R = 500\ \Omega + 500\ \Omega = 1000\ \Omega \]
Step 3: Apply Ohm’s law.
\[ I = \frac{V}{R} = \frac{10}{1000} = 0.01\ \text{A} = 10\ \text{mA} \]
• Forward biased $\rightarrow$ acts as short circuit
• Reverse biased $\rightarrow$ acts as open circuit
Step 1: Analyze diode directions.
From the circuit: - Only one conducting path is available due to diode orientations.
Step 2: Equivalent circuit.
Effective resistance in the conducting path: \[ R = 500\ \Omega + 500\ \Omega = 1000\ \Omega \]
Step 3: Apply Ohm’s law.
\[ I = \frac{V}{R} = \frac{10}{1000} = 0.01\ \text{A} = 10\ \text{mA} \]
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