Step 1: Understanding the Concept
Rolle's theorem needs \(f\) continuous on \([a,b]\), differentiable on \((a,b)\) and \(f(a)=f(b)\).
Step 2: Check the functions
\(f(x)=\log (x^{2}+2)-\log 3\) and \(e^{1-x^{2}}\) are even, smooth, with equal end values on \([-1,1]\). \(\sqrt{4-x^{2}}\) is continuous on \([-2,2]\), differentiable on \((-2,2)\) and \(f(\pm 2)=0\).
Step 3: The failing function
For \(f(x)=3+(x-1)^{2/3}\), \(f'(x)=\dfrac{2}{3}(x-1)^{-1/3}\) does not exist at \(x=1\), which lies in \((0,3)\).
Step 4: Conclusion
Rolle's theorem is not applicable to \(3+(x-1)^{2/3}\) on \([0,3]\). Also \(f(0)=4\neq f(3)=3+2^{2/3}\).
Final Answer:
Rolle's theorem fails for \(f(x)=3+(x-1)^{2/3}\) on \([0,3]\).
\[ \boxed{\text{(B) }f(x)=3+(x-1)^{2/3},\text{ on }[0,3]} \]