Question:

For the two mutually exclusive events \(A\) and \(B\), which of the following are correct? A. \(P(A\cup B)=P(A)+P(B)\)
B. \(P(A\cap B)=0\)
C. \(P(A\cap B)=P(A)\cdot P(B)\)
D. \(P(A\cap B)=P(A/B)P(B)\)
E. \(P(A)=P(A/B)P(B)\)

Show Hint

For mutually exclusive events, \(P(A\cap B)=0\) and \(P(A\cup B)=P(A)+P(B)\).
Updated On: Jun 6, 2026
  • A, C and E only
  • A, B and D only
  • A and D only
  • B, C only
Show Solution
collegedunia
Verified By Collegedunia

The Correct Option is B

Solution and Explanation

Concept:
Two events are mutually exclusive if they cannot occur together. \[ A\cap B=\phi \]

Step 1: Check A.

For mutually exclusive events: \[ P(A\cup B)=P(A)+P(B) \] So, A is correct.

Step 2: Check B.

Since events are mutually exclusive: \[ P(A\cap B)=0 \] So, B is correct.

Step 3: Check C.

The formula: \[ P(A\cap B)=P(A)P(B) \] is for independent events, not mutually exclusive events in general. So, C is incorrect.

Step 4: Check D.

By multiplication theorem: \[ P(A\cap B)=P(A/B)P(B) \] So, D is correct as a general probability identity. Thus: \[ A,B,D \] \[ \therefore \text{Correct Answer is (B)} \]
Was this answer helpful?
0
0

Top CUET PG Digital Systems Questions