Question:
For the circuit shown below, calculate the value of \(I_z\) :
For the circuit shown below, calculate the value of \(I_z\) :
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The Zener diode holds the voltage across the parallel branch at \(V_z = 50\ \mathrm{V}\). Find the current in \(R_s\) and subtract the current in \(R\).
Updated On: Nov 4, 2026
- 25 mA
- 0.1 A
- 0.15 A
- 0.05 A
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The Correct Option is A
Solution and Explanation
The Zener diode is in breakdown, so the voltage across it and across \(R\) is \(V_z = 50\ \mathrm{V}\).
Voltage across \(R_s\): \(100 - 50 = 50\ \mathrm{V}\).
Current through \(R_s\): \(I = \frac{50}{1000} = 0.05\ \mathrm{A} = 50\ \mathrm{mA}\).
Current through \(R\): \(I_R = \frac{50}{2000} = 0.025\ \mathrm{A} = 25\ \mathrm{mA}\).
By Kirchhoff's current law, \(I_z = I - I_R = 50 - 25 = 25\ \mathrm{mA}\).
Answer: (1) 25 mA
Voltage across \(R_s\): \(100 - 50 = 50\ \mathrm{V}\).
Current through \(R_s\): \(I = \frac{50}{1000} = 0.05\ \mathrm{A} = 50\ \mathrm{mA}\).
Current through \(R\): \(I_R = \frac{50}{2000} = 0.025\ \mathrm{A} = 25\ \mathrm{mA}\).
By Kirchhoff's current law, \(I_z = I - I_R = 50 - 25 = 25\ \mathrm{mA}\).
Answer: (1) 25 mA
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