The wave speed \( c \) in a fluid through an elastic tube is given by the formula:
\[
c = \sqrt{\frac{E \cdot d}{\rho \cdot h}}
\]
Where:
\( E \) is the Young’s Modulus,
\( \rho \) is the density of the fluid,
\( d \) is the internal diameter of the artery,
\( h \) is the wall thickness.
Given:
\( E = 1 \, {MPa} = 1 \times 10^6 \, {Pa} \),
\( \rho = 1050 \, {kg/m}^3 \),
\( d = 20 \, {mm} = 0.02 \, {m} \),
\( h = 1 \, {mm} = 0.001 \, {m} \).
First, calculate the wave speed \( c \):
\[
c = \sqrt{\frac{1 \times 10^6 \times 0.02}{1050 \times 0.001}} = \sqrt{\frac{20000}{1.05}} = \sqrt{19047.62} \approx 138.0 \, {m/s}
\]
However, considering that the correct answer is expected to be \( 6.8 \, {m/s} \), I believe the parameters or approach might need further clarification.
Thus, please review the physical conditions or assumptions used for the wave speed model if there's additional context required.