Question:
For \( f \)-orbital the values of \( m \) are
For \( f \)-orbital the values of \( m \) are
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Remember: For s (\(l=0\)), m=1 value; p (\(l=1\)), m=3 values; d (\(l=2\)), m=5 values; f (\(l=3\)), m=7 values.
Updated On: May 2, 2026
- \(-2, -1, 0, +1, +2\)
- \(-3, -2, -1, 0, +1, +2, +3\)
- \(-1, 0, +1\)
- \(0, +1, +2, +3\)
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The Correct Option is B
Solution and Explanation
Step 1: Understanding the Concept:
The magnetic quantum number \(m\) designates the orbital orientation. For a given azimuthal quantum number \(l\), \(m\) ranges from \(-l\) to \(+l\) including zero. For an \(f\)-orbital, \(l = 3\).
Step 2: Detailed Explanation:
If \(l = 3\), then \(m\) can have values: \(-3, -2, -1, 0, +1, +2, +3\). This gives a total of 7 orbitals.
Step 3: Final Answer:
Thus, the correct option is (B).
The magnetic quantum number \(m\) designates the orbital orientation. For a given azimuthal quantum number \(l\), \(m\) ranges from \(-l\) to \(+l\) including zero. For an \(f\)-orbital, \(l = 3\).
Step 2: Detailed Explanation:
If \(l = 3\), then \(m\) can have values: \(-3, -2, -1, 0, +1, +2, +3\). This gives a total of 7 orbitals.
Step 3: Final Answer:
Thus, the correct option is (B).
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