Question:

Which of the following sets of quantum numbers is impossible arrangement?

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$m$ ranges from $-l$ to $+l$, and $l$ ranges from $0$ to $n-1$.
Updated On: Apr 8, 2026
  • $n = 3, m = -2, s = +\frac{1}{2}$
  • $n = 4, m = 3, s = +\frac{1}{2}$
  • $n = 5, m = 2, s = -\frac{1}{2}$
  • $n = 3, m = -3, s = -\frac{1}{2}$
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The Correct Option is D

Solution and Explanation

Step 1: Understanding the Concept:
$m$ ranges from $-l$ to $+l$, and $l$ ranges from $0$ to $n-1$.
Step 2: Detailed Explanation:
For $n=3$, possible $m$ values are $-2,-1,0,1,2$. $m = -3$ is not possible.
Step 3: Final Answer:
The set with $n=3, m=-3$ is impossible.
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