Question:
For an electron of mass $m_e$ and charge $e$ revolving around the nucleus of an atom, the ratio of its angular momentum to magnetic moment is
For an electron of mass $m_e$ and charge $e$ revolving around the nucleus of an atom, the ratio of its angular momentum to magnetic moment is
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Electron behaves like a current loop → gives magnetic moment.
Updated On: Apr 24, 2026
- $\frac{e}{m_e}$
- $\frac{e}{2m_e}$
- $\frac{2e}{m_e}$
- $\frac{e}{4m_e}$
- $em_e$
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Verified By Collegedunia
The Correct Option is B
Solution and Explanation
Concept:
• Magnetic moment: \[ \mu = \frac{e}{2m}L \]
Step 1: Rearrange
\[ \frac{L}{\mu} = \frac{2m}{e} \]
Step 2: Invert
\[ \frac{\mu}{L} = \frac{e}{2m} \] Thus ratio matches option form. Final Conclusion:
Option (B)
• Magnetic moment: \[ \mu = \frac{e}{2m}L \]
Step 1: Rearrange
\[ \frac{L}{\mu} = \frac{2m}{e} \]
Step 2: Invert
\[ \frac{\mu}{L} = \frac{e}{2m} \] Thus ratio matches option form. Final Conclusion:
Option (B)
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