Step 1: Identify the nature of the reaction.
The reaction is
\[
A(g)+\frac{1}{2}B(g)\rightleftharpoons C(g)+\text{heat}
\]
Since heat is produced on the product side, the forward reaction is
exothermic
Step 2: Effect of temperature using Le Chatelier’s principle.
For an exothermic reaction, heat behaves like a product.
When temperature is decreased, the equilibrium shifts in the forward direction to produce more heat.
Therefore,
Low temperature favors the forward reaction.
Step 3: Effect of pressure.
Count the number of moles of gaseous reactants and products.
Reactant side:
\[
1+\frac{1}{2}=1.5 \text{ moles of gas}
\]
Product side:
\[
1 \text{ mole of gas}
\]
Since the number of gaseous moles decreases in the forward direction, increasing pressure shifts the equilibrium towards the side with fewer moles.
Therefore,
High pressure favors the forward reaction.
Step 4: Final conclusion.
Hence, the favorable conditions are
\[
\boxed{\text{Low }T\text{ and High }P}
\]