Question:

For a monatomic gas, the molar specific heat at constant pressure divided by the molar gas constant \(R\) is equal to

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For monatomic gas: \(C_v = \frac{3}{2}R\), \(C_p = \frac{5}{2}R\).
Updated On: May 8, 2026
  • 2.5
  • 1.5
  • 5.0
  • 3.5
  • 4.0
Show Solution
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The Correct Option is A

Solution and Explanation

Concept: For a monatomic gas: \[ C_v = \frac{3}{2}R, \quad C_p = C_v + R = \frac{5}{2}R \]

Step 1:
Write expression. \[ \frac{C_p}{R} = \frac{5}{2} \]

Step 2:
Simplify. \[ = 2.5 \]

Step 3:
Conclusion. \[ \boxed{2.5} \]
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