Question:

For a diatomic gas molecule the value of \(C_p\) in \(J mol^{-1} K^{-1}\) is \((R = 8.2 J mol^{-1} K^{-1})\)

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For monatomic gas: \(C_v = 3R/2\), \(C_p = 5R/2\). For diatomic: \(C_v = 5R/2\), \(C_p = 7R/2\).
Updated On: Apr 24, 2026
  • 20.5
  • 41
  • 10.25
  • 12.3
  • 28.7
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Solution and Explanation

Step 1: Understanding the Concept:
The molar heat capacities for an ideal gas depend on the degrees of freedom. For a diatomic molecule at moderate temperatures, \(C_v = \frac{5}{2}R\) and \(C_p = C_v + R = \frac{7}{2}R\).

Step 2:
Detailed Explanation:
Given \(R = 8.2 \, J mol^{-1} K^{-1}\). For a diatomic gas, \(C_p = \frac{7}{2} R\). \[ C_p = \frac{7}{2} \times 8.2 = 3.5 \times 8.2 = 28.7 \, J mol^{-1} K^{-1} \]

Step 3:
Final Answer:
The value of \(C_p\) is \(28.7 \, J mol^{-1} K^{-1}\).
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